FieldsService operations and logistics
Experiments here usually have about 3 factors and 16 runs. Most are full factorials.
- Full factorial
- Fractional factorial or screening
Show the numbers
| Kind of design | Experiments | Factors | Runs |
|---|---|---|---|
| Full factorial | 8 | 2.5 | 10 |
| Fractional factorial or screening | 5 | 5 | 16 |
Factors and runs are the medians of each kind.
Full factorial
Every combination of the factor levels.
- Departure wait times at Hamilton airport: check-in staff C, kiosk staff K and security staff SDunn (2015) · 3 factors, 8 runs
- Pizza delivery time: crust A, soft drinks B and garlic bread C, and the Pareto plot of its modelDunn (2015) · 3 factors, 8 runs
- Rise in heart rate moving the cases of Problem 6.9: bottle type by worker, a 2^2 run four times (Problem 6.10)Montgomery (2013) · 2 factors, 4 runs
- Time to deliver 12-bottle cases: glass or plastic bottles, two workers, a 2^2 run four times (Problem 6.9)Montgomery (2013) · 2 factors, 4 runs
- Time to stock ten 12-bottle cases: three bottle types, three shelf types and three workers, a 3^3 run twice (Problem 9.3)Montgomery (2013) · 3 factors, 54 runs
Show the rest
- Yield of a product from three machines at two power settings, three stations on each machine and three observations a station (Problem 14.13)Montgomery (2013) · 3 factors, 54 runs
- Commute times by three routes, leaving early or late: a 3 x 2 general factorial replicated twice (Problem 7-2)Anderson and Whitcomb (2007) · 2 factors, 12 runs
- Units produced per day by four operators on five machines, each combination on two days spread over 84 working days (Problems 11 and 12 of Part II)Box, Hunter and Hunter (1978) · 2 factors, 40 runs
Fractional factorial or screening
A planned part of the combinations, to find the factors that matter.
- Average annual cost of a simulated inventory system: order quantity, reorder point, setup cost, backorder cost and carrying cost rate, a 2^(5-2) and two more fractions (Problem 8.23)Montgomery (2013) · 5 factors, 24 runs
- Total cost of a simulated two-item inventory system against each item's order quantity and reorder point (Problem 11.2)Montgomery (2013) · 4 factors, 11 runs
- Time to pack 100 standard items: a 2_III^(7-4) with I = -126 = 135 = -237 = -1234, then its fold-over (Exercise 5.27)Box and Draper (2007) · 3 factors, 16 runs
- Time to pack 100 standard items: the two 2_III^(7-4) tables of the answer, with columns 4 to 7, analysed apart and together (Exercise 5.27)Box and Draper (2007) · 7 factors, 16 runs
- Sensitivity analysis of an air traffic control simulation: eight factors in a 2^(8-4) fractionBox, Hunter and Hunter (1978) · 8 factors, 16 runs